-34=x^2-14x+10

Solution for -34=x^2-14x+10 equation:

-34=x^2-14x+10

We move all terms to the left:

-34-(x^2-14x+10)=0

We get rid of parentheses

-x^2+14x-10-34=0

We add all the numbers together, and all the variables

-1x^2+14x-44=0

a = -1; b = 14; c = -44;
Δ = b2-4ac
Δ = 142-4·(-1)·(-44)
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{5}}{2*-1}=\frac{-14-2\sqrt{5}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{5}}{2*-1}=\frac{-14+2\sqrt{5}}{-2}
$